(1)* >When I put a heavy hub/heavy prop on a Fox 35 the shaft
>broke right at the front of the case, under the prop driver.
>
>When I broke one from too much nitro, it broke across the
>port.
>
(2)* >I'd bet you can break almost any engine with a 12mm ball
>bearing shaft simply by letting it rev. Most of them, from
>25-36 will happily turn an 8/5 or 8/6 prop upwards of
>18-20,000 before breaking the shaft across the port. I've
>proved to myself more times than I should have that a 12mm
>shaft is not strong enough to pull a combat plane over 90
>mph. I have never heard of anyone breaking this size shaft
>in a stunt application.
>
(3)* >A front intake shaft port is a horrible design solution-
>huge stress risers, twisting loads, terrible fatigue life,
>bad resonance problems at common useful rpms(typical FI
>engine will vibrate badly at ~7500 rpm, 15,000 rpm, 22500
>rpm, and something over 30,000). The G-21.35 would often
>break the shaft just when the motor started running well,
>around 15,000 or so. The AKM folks specifically tell you
>not to run the their motors over 30,000 because the shaft
>will break.
Ron B.
F4Fguy
Phil:
My criticism is not with the idea that the crank will fail, or even, where. It was that the mode of failure was torsional in nature. Certainly operating at a nodal frequency will bring failure earlier, that doesn't alter the mode of failure. Whether coincident or not, the part will fail when the fatigue limit is reached at the point of highest stress.
*(1) Adding rotational mass forward on the shaft will move the point of max stress forward. As an example: Consider what would happen if you moved the flywheel on a car to the final drive (assuming front engine, rear drive). The power delivery to the wheels would not be significantly changed but, the reversal loads on the transmission would quickly destroy it or the drive line in between. If you doubt this, talk to an ALFA owner with an Alfetta, which has the clutch in the rear at the final drive. They eat drive lines. The high nitro example is actually an example of what I'm trying to convey; the resistance is primarily from the prop, there's no great inertial mass, the force at the crankpin is dramatically increased, so the failure point is as predicted, at the port.
*(2) Only true if you are still running a prop for load, in which case the failure will still be torsional fatigue, and most likely at the port. It will be induced by the cyclic load imposed by the rotating prop and the nature of the pressure curve. If you shaft run with no load the failure will probably be at the crankpin (or, more likely, the rod). That is assuming the bearings will allow continued operation at this speed. Once a bearing failure occurs, all bets are off, as the crank is now subject to eccentricity and friction which changes everything.
*(3) No argument! On the other hand, it's the lightest, simplest, least complicated, lowest cost solution to the two stroke conundrum. I don't know about you but, I don't want to return to side ports.