There are several possibilities:
Along with your leadout shift, you might check to see that the engine is pointing straight ahead.
However, most of the pull (I think) is probably "centrifugal" force. This pull is going as
mass*(velocity^2)/radius.
If I calculate this using your "raw" numbers (64 oz->1.8kg, 64 feet->19.5m, velocity=22.7m/s=43mph), I find that the centrifugal force that you are experiencing is "only" ~10.4 lbs (~48N)!
I may be using too short a distance (64 feet) for the radius, since that ignores your arm length, and half the wingspan. (so the force might be somewhat less). So either your estimated pull is off, or you really have a lot of yaw on this plane.
Since the mass of your plane is fixed (I assume!), you can play with line length (radius) or plane speed. So from Paul W's comment, going from 64 foot lines to 70 foot would reduce the pull by 91% (so 10 lbs->~9 lbs). I am not sure if this is actually possible since the radius actually includes your line length+1/2 the wingspan, + arm length, whereas does the 70 foot max length include the wingspan plus arm length( ??).
If you slow the plane down to lets say 5.8 second laps, the velocity would decrease by 93%, but since it enters as the square, your pull would decrease by a 87% factor (so 10 lbs ->8.7lbs.
If you do both (increase line length, and decrease velocity, you might get to 8 lbs of pull or so.
Maybe the weight training is a good idea!